![]() I spent about 90 minutes typing in an explanatory post with two lengthy tables and then something happened and my browser lost the post. :]Īny chance you care to show the details of your work? Solve for whatever you like, however you like. This seems awful low, and doesn't account for the dealer not having it, as well as only counting 3+ card 21 draws. ![]() Any help/contribution/jumble of formulas/estimates welcome. I'm interested in the following situational question - In a standard Double Deck game, What is the probability of being dealt a two card 20 as a starting hand, the dealer having an Ace up, and the player not taking insurance, and the dealer not having a blackjack, and the dealer drawing to a 5 card 21? What is the probability the same occuring, but being dealt a two card combination without including A,9 combos? For some reason when I do the math of the 52,2 20 combos by hand for % P = x/y, My brain freezes up :x. Moreover, is my math estimate of probability a * probability b * probability c * probability d = final probability a valid way to solve this problem or not? Thanks for reading? ![]() I'm less interested in a final answer and more interested in a process to answer the following question.
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